A small UA has an unaccelerated stalling speed of 50 knots. Using the load factor for a 60° bank from the Load Factor Chart (Figure 2), and the rule that stalling speed increases with the square root of load factor, what is the approximate stalling speed in a coordinated, level 60° banked turn?

Why: Figure 2 gives a load factor of 2.000 G at a 60° bank. The Remote Pilot Study Guide states that "an aircraft's stalling speed increases in proportion to the square root of the load factor" — for example, a 50-knot aircraft stalls at 100 knots under a load factor of 4 Gs, since √4 = 2. Applying the same rule here: 50 kt × √2.000 ≈ 50 × 1.414 ≈ 71 knots.

• Multiplies the unaccelerated stalling speed by the load factor itself instead of by its square root, overstating the increase — that method would only be correct if load factor increased stalling speed linearly, which it does not.
• Ignores the load factor relationship entirely, assuming stalling speed is unaffected by bank angle, when a steeper bank increases load factor and therefore raises the stalling speed.